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Home/Grade 4 & 5 Chemistry: Free Trial*

G. 10 & 11

Chemistry

F. 4 & 5

Hello , welcome to QuizTime @ Quantum Solverz!
  • This MCQ  is a great way to help you revise this topic.
  • You will get 10 random questions for 20 minutes each time you take the quiz. Good luck!

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G. 10 & 11 / F. 4 & 5

Chemistry: Free Trial*

MCQs

Welcome to KuizTime @ Quantum Solverz.

1 / 10

1. Ionic bonding usually occurs between what type of atoms?

Sorry, that is incorrect.

Two metals joining together form an alloy with metallic bonding, two non-metals will form covalent bonds and, at GCE O-level, noble gases are regarded as being inert

Correct!

Two metals joining together form an alloy with metallic bonding, two non-metals will form covalent bonds and, at GCE O-level, noble gases are regarded as being inert

2 / 10

2. The ionic bonds that exist between charged particles result in an arrangement that is called...

Sorry, that is incorrect.

There are no limits to the size of a giant ionic lattice other than the number of ions available

Correct!

There are no limits to the size of a giant ionic lattice other than the number of ions available

3 / 10

3. What is a reversible reaction?

Sorry, that is incorrect.

A good example of a reversible reaction is the formation of ammonia from hydrogen and nitrogen

Correct!

A good example of a reversible reaction is the formation of ammonia from hydrogen and nitrogen

4 / 10

4. A water molecule is covalently bonded. How many covalent bonds does it have?

Sorry, that is incorrect.

Oxygen has a valency of 2 so it only ever forms two covalent bonds. You can work this out for yourself from the electron structure

Correct!

Oxygen has a valency of 2 so it only ever forms two covalent bonds. You can work this out for yourself from the electron structure

5 / 10

5. In a titration I use 25 $cm^{3}$ of 0.20 $moldm^{-3}$ sodium hydroxide solution and find that it is neutralised by exactly 21 $cm^{3}$ of hydrochloric acid. What is the concentration of the hydrochloric acid solution?

$HCl + NaOH \longrightarrow NaCl + H_{2}O$

Sorry, that is incorrect.

When doing this type of calculation, always start with the solution that you know most about, in this case, the sodium hydroxide solution. Since you know both the volume and the concentration you can calculate how many moles of sodium hydroxide you have. Next, look at the equation for the reaction; one mole of sodium hydroxide reacts exactly with one mole of hydrochloric acid. You therefore know how many moles of HCl there must have been in 21 $cm^{3}$ of solution. Since you know moles and volume, you can calculate the concentration.

Correct!

When doing this type of calculation, always start with the solution that you know most about, in this case, the sodium hydroxide solution. Since you know both the volume and the concentration you can calculate how many moles of sodium hydroxide you have. Next, look at the equation for the reaction; one mole of sodium hydroxide reacts exactly with one mole of hydrochloric acid. You therefore know how many moles of HCl there must have been in 21 $cm^{3}$ of solution. Since you know moles and volume, you can calculate the concentration.

6 / 10

6. I have 2 $dm^{3}$ of carbon dioxide gas at room temperature and pressure. How many moles do I have?

Sorry, that is incorrect.

The key fact to remember here is that one mole of any gas occupies 24 $dm^{3}$ at RTP. I have 1/12 of this volume, so I must have 1/12 of a mole

Correct!

The key fact to remember here is that one mole of any gas occupies 24 $dm^{3}$ at RTP. I have 1/12 of this volume, so I must have 1/12 of a mole

7 / 10

7. In the following reaction, if I fully react 4g of methane, what mass of water should I expect to make?

$CH_{4} + 2O_{2} \longrightarrow CO_{2} + 2H_{2}O$

Sorry, that is incorrect.

This is a reacting mass calculation. If you start with a known mass of a chemical, by using its $M_{r}$ you can work out how many moles of it you have. In this case, we have 0.25 mol of methane. You can then use the stoichiometry of the reaction (aka the big balancing numbers!) to show you that every one mole of methane produces 2 moles of water. So we deduce that 0.5 mol of water will be made. Then you simply need to use $mass = moles \times M_{r}$ to calculate the mass of water produced

Correct!

This is a reacting mass calculation. If you start with a known mass of a chemical, by using its $M_{r}$ you can work out how many moles of it you have. In this case, we have 0.25 mol of methane. You can then use the stoichiometry of the reaction (aka the big balancing numbers!) to show you that every one mole of methane produces 2 moles of water. So we deduce that 0.5 mol of water will be made. Then you simply need to use $mass = moles \times M_{r}$ to calculate the mass of water produced

8 / 10

8. $\Delta$H is negative for what type of reactions?

Sorry, that is incorrect.

On an energy level diagram, the energy contained in the bonds of the products is less than that of the reactants

Correct!

On an energy level diagram, the energy contained in the bonds of the products is less than that of the reactants

9 / 10

9. $\Delta$H is positive for what type of reactions?

Sorry, that is incorrect.

On an energy level diagram, the energy contained in the bonds of the products is greater than that of the reactants

Correct!

On an energy level diagram, the energy contained in the bonds of the products is greater than that of the reactants

10 / 10

10. What is the electronic configuration for an $Al^{3+}$ ion?

Sorry, that is incorrect.

Aluminium loses 3 electrons from its outer shell, giving it a charge of $+3$

Correct!

Aluminium loses 3 electrons from its outer shell, giving it a charge of $+3$

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